Vedic maths › Vertically and crosswise

Vertically and crosswise: multiplying any two numbers

ऊर्ध्वतिर्यग्भ्याम् Ūrdhva-tiryagbhyām “vertically and crosswise”, a sutra of Vedic maths.

Ūrdhva-tiryagbhyām, “vertically and crosswise”, is the general multiplication method of Vedic maths: it works for any two numbers, not just special ones. It builds the answer one place at a time, so the working fits on one line, or in your head.

The idea is much older than the sutra: Indian mathematicians such as Śrīdhara and Mahāvīra taught this kind of cross-multiplication more than a thousand years ago.

The method

  1. Write one number above the other.
  2. Vertically on the left: multiply the first digits. That is the first part of the answer.
  3. Crosswise: multiply the first digit of each number by the last digit of the other, and add. That is the middle part.
  4. Vertically on the right: multiply the last digits. That is the last part.
  5. Each part keeps one digit: carry the rest to the part on its left, starting from the right.

Worked examples

23 × 41

  1. Vertically on the left: the first digits.2 × 4 = 8
  2. Crosswise: first by last, and last by first.2 × 1 + 3 × 4 = 2 + 12 = 14
  3. Vertically on the right: the last digits.3 × 1 = 3
  4. Put the parts side by side.8 | 14 | 3
  5. Carry from the right, keeping one digit in each part.3; 14: keep 4, carry 1; 8 + 1 = 9 → 943

23 × 41 = 943

67 × 58

  1. Vertically on the left: the first digits.6 × 5 = 30
  2. Crosswise: first by last, and last by first.6 × 8 + 7 × 5 = 48 + 35 = 83
  3. Vertically on the right: the last digits.7 × 8 = 56
  4. Put the parts side by side.30 | 83 | 56
  5. Carry from the right, keeping one digit in each part.56: keep 6, carry 5; 83 + 5 = 88: keep 8, carry 8; 30 + 8 = 38 → 3886

67 × 58 = 3886

213 × 132

  1. Vertically on the left: the first digits.2 × 1 = 2
  2. Crosswise on the left: the first two digits of each.2 × 3 + 1 × 1 = 6 + 1 = 7
  3. The big cross: first by last, middle by middle, last by first.2 × 2 + 1 × 3 + 3 × 1 = 4 + 3 + 3 = 10
  4. Crosswise on the right: the last two digits of each.1 × 2 + 3 × 3 = 2 + 9 = 11
  5. Vertically on the right: the last digits.3 × 2 = 6
  6. Put the parts side by side.2 | 7 | 10 | 11 | 6
  7. Carry from the right, keeping one digit in each part.6; 11: keep 1, carry 1; 10 + 1 = 11: keep 1, carry 1; 7 + 1 = 8; 2 → 28116

213 × 132 = 28116

Why it works

A two-digit number is 10a + b. So (10a + b)(10c + d) = 100 × ac + 10 × (ad + bc) + bd: the vertical and crosswise products are the hundreds, tens and units of the answer. A part bigger than 9 spills into the next place, which is the carry.

With three digits there are five places, and each one collects every product whose two digits’ places add up to it. That is why the middle place has three products: the big cross.

Watch out

Try these

Work each one out, then tap it to see the answer.

  1. 32 × 21

    6 | 7 | 2 → 672

  2. 46 × 37

    12 | 46 | 42 → 1702

  3. 84 × 26

    16 | 56 | 24 → 2184

  4. 123 × 211

    2 | 5 | 9 | 5 | 3 → 25953

  5. 312 × 124

    3 | 7 | 16 | 8 | 8 → 38688

Practise it in the game: Maths, the multiplication levels. Free, with no sign-up.

Source: This method is from Bharati Krishna Tirtha’s Vedic Mathematics (1965). The explanation, examples and questions here are our own.

More Vedic maths

Where Vedic maths comes from, all 16 sutras, and our sources: Vedic maths, explained.